Question

The measured mass and volume of a body or 2.42 g and 4.7 cm³ respectively with possible errors 0.01 g and 0.1 cm³. Find the maximum error in density

Answer 1

Given :

Mass =m=2..42g

Volume=v=4.7cm3

Δm=0.01g

Δv=0.1cm3

Density (ρ)=mass/volume

Δρ/ρ=Δm/m+Δv/v

=0.01/2.42+0.1/4.7

=0.004+0.02=0.024

%error is Δρ/ρ  x100

=0.024x100

=2.4% ≈nearly 2% ∴

maximum error in density is 2%

Answer 2

Hii mate,

# Answer- 2 %.

# Given-
m = 2.42 g
v = 4.7 cm^3
Δm = 0.01 g
Δv = 0.1 cm^3

# Explaination-
Let's solve this step-by-step.

First we'll calculate percentage error in measuring mass and volume.
Δm/m×100 = 0.01/2.42×100 = 0.413%
Δv/v×100 = 0.1/4.7×100 = 2.13%

Density = mass/volume

Percentage error in density,
Δd/d×100 = Δm/m×100 + Δv/v×100
Δd/d×100 = 0.413%+2.13%
Δd/d×100 = 2.5%

Percentage error in density is 2.5%.

Hope that was useful...