The measurements of the electron position associated with an uncertainty in momentum which is equal to 1×10^-18 g cm/s . the uncertainty in electron velocity is
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∆P=1×10^18g cms^-1
m=9×10^28g
so, as we know ∆P=m∆v
∆v=∆p/m
=1×10^18/9×10^28
=1×10^9 C
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m=9×10^28g
so, as we know ∆P=m∆v
∆v=∆p/m
=1×10^18/9×10^28
=1×10^9 C
thanks for asking the question,if u r getting help by my solution than click on a red cardiac type structure.....
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