Question

the measures if angles of quadrileteral in degrees are x , 3x-40 , 2x , 4x+ 20 . find the measures of angles

Answer 1

the sum of quadrilateral = 360
x + 3x-40 + 2x + 4x + 20 = 360
10x -20 = 360
10x = 360+20
10x =380
x = 38
first angle = 38
second angle = 74
third angle = 76
fourth angle = 192

Answer 2

Answer :-

• 38°
• 74°
• 76°
• 172°

Given :-

• The angles of a quadrilateral are x, (3x - 40), 2x, (4x + 20)

To Find :-

• Measure of the angles n

Solution :-

As we know that

Sum of all angles of a quadrilateral is 360°

According to question :-

x + (3x - 40) + 2x + (4x + 20) = 360

→ x + 3x - 40 + 2x + 4x + 20 = 360

→ x + 3x + 2x + 4x - 40 + 20 = 360

→ 10x - 20 = 360

→ 10x = 360 + 20

→ 10x = 380

→ x = 38°

Now

Angles are,

• x = 38°
• 3x - 40 = 3(38) - 40 = 74°
• 2x = 2 × 38 = 76°
• 4x + 20 = 4(38) + 20 = 172°

Hence, the angles are 38°, 74°, 76° and 172° respectively.