Math, asked by suhanigupta720, 4 months ago

The measures of a rectangular field are 20 m by 15 m. A cubical ditch of edge 4 m is dug at each
the four corners of the field and the removed soil is spread uniformly over the remaining field.
what height does the field get raised?
A rectangular bollow pipe is made of 1-cm-thick iron sheet. If the length of the pipe is 2 manda​

Answers

Answered by Sujalkumartarai
1

The measures of rectangular field are 20m by 15m = ( 20 × 15 ) m = 300m.

A cubical ditch of edge is dug at each = 4m3 ( Suppose ).

The four corners of the field and the removed soil is spread uniformly over the remaining field = 4 ( 4x - 300 ) m3 = 16x - 300m3 = 16x - 1200m3.

Area = 1/2 × base × height

= 1/2 × 300 × h = 150 h

= h= 150.

Total of the expression

16x - 1200m3.

A rectangular bollov pipe is made of thick iron sheet = 1cm.

1cm = 1000m.

Length of pipe = 2 manda

2 ( l + b ) m3

= 2 ( 2 + 4 ) m3

= 4 + 4 m3

= 8m3 ( Ans )

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