The measures of a text book are 22 cm×11cm×3cm. It is to be covered with a brown paper. If each book requires 164cm2 of more paper for folding, how much paper is required to wrap 85 such text books?
Pls answer
Answers
Answer :-
paper required = 60690 cm²
Explanation :-
If a text book is to be covered with paper then only there need to cover .
so , we have to cover top surface, bottom surface and one side surface
Now ,
Area of top surface = Area of bottom surface = 22 cm X 11cm = 242 cm²
Area of the side surface = 22cm X 3 cm = 66 cm²
Total surface area to be covered = 242+ 242 + 66 = 550 cm²
Paper reqd for folding = 164 cm²
Total paper reqd for one book = 550 + 164 = 714 cm²
Total paper reqd for 85 books= 85 × 714 = 60690 cm²
Question:-
The measures of a text book are 22 cm×11cm×3cm. It is to be covered with a brown paper. If each book requires 164² of more paper for folding, how much paper is required to wrap 85 such text books?
Given:-
- The measures of a textbook are 22cm × 11cm × 3cm.
To Find:-
- Paper required to wrap 85 such textbooks.
Solution:-
- Length of book (l) = 22cm.
- Breadth of book (b) = 11cm.
- Height of book (h) = 3cm.
Surfaces to be covered are:-
AEHD (front), BFGC(back), ABEF(side).
Surface area of AEHD = Surface of BFGC.
= 2 × (l × b)
= 2 × (22 × 11)cm²
= 484cm².
Surface area of ABEF = l × h (22 × 3)cm² = 66cm².
Area of paper required for folding = 164cm².
∴ Total area of paper required =
(484 + 66 + 164)cm².
Area of paper required for 85 books = (85 × 714)cm².
= 60,690cm².
Answer:-
∴ Area of paper required to cover 85 textbooks is 60,690cm².
