the measures of an angle is five times the measure its supplementry angle . find its angle
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let the angle be x ,...its supplementary angle=180-x
ATQ,
x=5(180-x)
or, x=900-5x
or, 6x=900
or. x=150
so the angles are 150° and 30°
ATQ,
x=5(180-x)
or, x=900-5x
or, 6x=900
or. x=150
so the angles are 150° and 30°
tanishqsingh:
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let the angle=x
so its supplementary=180-x
given that x is 5 ties its supplement
so,x=5(180°-x)
⇒x=900°-5x
⇒x+5x=900°
⇒6x=900°
⇒x=900°÷6
⇒x=150°
so its supplementary=180-x
given that x is 5 ties its supplement
so,x=5(180°-x)
⇒x=900°-5x
⇒x+5x=900°
⇒6x=900°
⇒x=900°÷6
⇒x=150°
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