Math, asked by oy743957, 16 days ago

The measures of angles of a quadrilateral in degrees are x,3x−30,2x and 4x-40. Find the measure of each angle.​

Answers

Answered by aswathyaswany123
1

Step-by-step explanation:

Given, x,(3x−40),2x,(4x+20).

We know, by angle sum property, the sum of the angles of  a quadrilateral is 3600.

Therefore, x+(3x−40)+2x+(4x+20)=360o

⇒10x−20o=360o

⇒10x=360o+20o=380o

⇒x=10380o=38o.

Now, x=38o,

2x=2×38o=76o,

3x−40o=3×38o−40o=74o

and 4x+20o=4×38o+20o=172o.

Answered by jesal07778
0

Sum of the angles of a Quadilateral = 360°

x + 3x - 30 + 2x + 4x - 40 = 360

10x - 70 = 360

10x = 430

x = 43

M of Each Angle :-

x = 43

3x - 30 = 99

2x = 86

4x - 40 = 132

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