The measures of angles of a quadrilateral in degrees are x,3x−30,2x and 4x-40. Find the measure of each angle.
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Answered by
1
Step-by-step explanation:
Given, x,(3x−40),2x,(4x+20).
We know, by angle sum property, the sum of the angles of a quadrilateral is 3600.
Therefore, x+(3x−40)+2x+(4x+20)=360o
⇒10x−20o=360o
⇒10x=360o+20o=380o
⇒x=10380o=38o.
Now, x=38o,
2x=2×38o=76o,
3x−40o=3×38o−40o=74o
and 4x+20o=4×38o+20o=172o.
Answered by
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Sum of the angles of a Quadilateral = 360°
x + 3x - 30 + 2x + 4x - 40 = 360
10x - 70 = 360
10x = 430
x = 43
M of Each Angle :-
x = 43
3x - 30 = 99
2x = 86
4x - 40 = 132
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