Question

The measures of angles of a triangle are

x°, (x - 20), (x-40). Find the measure of each angle.​

Answer 1

Step-by-step explanation:

Sum of angles in a triangle = (n-2)× 180° where n is the number of side

Number of sides in a triangle = 3

Sum of interior angles=( 3-2)× 180° = 180°

Given that,

1st angle = x°

2nd angle (x - 20)°

3rd angle = (x-40)°

So, an equation will be formed

x° + x° - 20° + x° - 40° = 180°

regrouping the terms in LHS ,

we have,

x° + x° + x° - 20° - 40° = 180°

3x° - 60° = 180°

3x = 180° + 60°

3x = 240°

x = \frac{240}{3}x=

3

240

x = 80

So,

1st angle = x = 80°

2nd angle = x -20° = 80° - 20° = 60°

3rd angle = x - 40° = 80° - 40° = 40°

Thus,

the angles of the given triangle 80° , 60° and 40°

Answer 2

Step-by-step explanation:

x + (×-20) + (×-40 ) = 180

3x -60 = 180

3x = 240

x = 80

1st angle x is 80

2nd angle ( x-20 ) is 60

3rd angle ( x-40 ) = 40