Question

The measures of angles of a triangle are xº, (x-20)º, (x-40).
find the measure of each angle
​

Answer 1

Answer:

Step-by-step explanation:

We know that, sum of all angles = 180°

Then if we add given angles

This gives us

(3x-60)°=180°

3x=180°+60=240°

X=240°/3

= 80°.

So,the three angles are

80°,60°&40°.

Answer 2

Step-by-step explanation:

given

$< x = {x}^{0} \\ < y = ( {x - 20}^{0} ) \\ < z = {(x - 40)}^{0} \\ \\ now \: as \: we \: know \\ sum \: of \: all \: angle \: of \: triangle \: = 180 \\ \\ < x + < y + < z = 180 \\ \\ put \: all \: the \: values \\ \\ x + x - 20 + x - 40 = 180 \\ \\ 3x - 60 = 180 \\ \\ 3x = 180 + 60 \\ \\ 3x = 240 \\ \\ x = \frac{240}{3 } \\ x = 80 \\ \\ < x = 80 \\ < y = x - 20 = 80 - 20 = 60 \\ \\ < z = x - 40 = 80 - 40 = 40$