Question

The measures of angles of a triangles are in a ratio of 5:6:7 then find the measures of all the angles ​

Answer 1

Solution

Given :-

• Radio of angle of triangle = 5:6:7

Find :-

• All angle of triangle

Explanation

Let,

• First angle be = 5x
• Second angle be = 6x
• Third angle be = 7x

We Know,

All angle of triangle always be 180°.

So,

➡ 5x + 6x + 7x = 180

➡18x = 180

➡x = 180/18

➡x = 10

Hence

• First angle be = 5x = 5 × 10= 50°
• Second angle be = 6x = 6×10 = 60°
• Third angle be = 7x = 7×10= 70

____________

Answer 2

$\huge{\underline{\overline{\mid{\mathfrak{\purple{\:\: SOLUTION\:\:} \mid}}}}}$

$\underline{ \mathfrak{ \: AnswEr:- \: }}$

• $\text{ \green{The first angle = 50\degree}}$
• $\text{ \red{The second angle = 60\degree}}$
• $\text{ \green{The third angle = 70\degree}}$

$\underline{ \mathfrak{ \: Given:- \: }}$

$\text{ \orange{The measures of angles of a triangles}} \\ \text{\orange { are in a ratio of 5:6:7.}}$

$\underline{ \mathfrak{ \: Need \:\: to \:\: find:-\: }}$

$\text{\red{\:\:The measures of all the angles = ?}}$

$\underline{ \mathfrak{ \:Let:- \: }}$

• $\text{ \green{The first angle be 5y.}}$
• $\text{ \red{The second angle be 6y.}}$
• $\text{ \green{The third angle be 7y. }}$

$\underline{ \mathfrak{ \: \: As,\:We \: \: know \: \: that:- \: \: }}$

$\: \: \: \: \: \: \: \: \: \: \: \sf{All \:angles\: of \:the \:\triangle = 180\degree}$

$\underline{ \mathfrak{ \: Therefore:- \: }}$

$\sf{ \longrightarrow \:5y + 6y + 7y = 180 }$

$\sf{ \longrightarrow \:18y = 180 }$

$\sf{ \longrightarrow \: y = \cancel\dfrac{180}{18} }$

$\sf{\longrightarrow\:y = 10}$

$\underline{ \mathfrak{ \: \: Hence:- \: \: }}$

• $\text{ \green{The first angle = 50\degree}}$
• $\text{ \red{The second angle = 60\degree}}$
• $\text{ \green{The third angle = 70\degree}}$

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