Question

The measures of sides of a triangle are in A.P it's perimeter is 30cm and difference between longest and shortest side is 4 cm find the measures of sides answer soon plz....

Answer 1

HOLA MATE HERE IS UR ANSWER ♥♥♥

The three sides are a,(a+d),(a+2d)a,(a+d),(a+2d), the area of right angled triangle is 24. Hence

12a(a+d)=2412a(a+d)=24

a(a+d)=48a(a+d)=48 - product of two sides = 48

All possibilities - x,yx,y

1,481,48 —a=1,d=47a=1,d=47

2,242,24 — a=2,d=22a=2,d=22 (third side z=46)z=46)

3,163,16 —a=3,d=13a=3,d=13 (third side = z=29)z=29)

4,124,12 — a=4,d=8a=4,d=8 (third side = z=20)z=20)

6,86,8 — a=6,d=2a=6,d=2 (third side = z=10)z=10)

But for right angles triangle, you want -

x2+y2=z2x2+y2=z2

Only (6,8,10)(6,8,10), satisfy this. So these are the sides of your triangle, smallest side being 66.

I HOPE IT WILL HELP YOU DEAR
THANKU

Answer 2

Answer:

The sides are 8,10 and 12

Step-by-step explanation:

As per the data given in the question we have to calculate the sides.

As per the questions it is given that the measures of sides of a triangle are in A.P it's perimeter is 30cm and difference between longest and shortest side is 4 cm.

Let us assume that the sides be a-d, a, a+d

Here a is the number and d is the difference.

A-d is the shortest and a+d is the longest site.

(a+d)-(a-d)=4

⇒2d=4 = d= 2

Perimeter is given as 30cm

a-d+a+a+d = 30

⇒a=10cm

a-d = 10-2 = 8cm

a = 10cm

a+d = 10+2 12 cm

Therefore, the sides are 8,10 and 12.

Hence, the sides are 8,10 and 12

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https://brainly.in/question/13742618

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