Math, asked by sgabrielsinclair, 18 days ago

The measures of the exterior angles of an octagon are x°, 2x°, 3x°, 4x°, 5x°, 6x°, 9x°, and 10x°

Answers

Answered by rajeebsc001
0

Answer:

x°+2x°+3x°+4x°+5x°+6x°+9x°+10x° = 360°

40x° = 360°

x° = 9°

x° = 9°

2x° = 18°

3x° = 27°

4x° = 36°

5x° = 45°

6x° = 54°

9x° = 81°

10x° = 90°

Answered by piyushsinghshrinet7
0
  • ANSWER-

Sum of all exterior angles in any regular polygon figure = 360°

x + 2x + 3x + 4x + 5x + 6x + 9x + 10x = 360°

40x = 360°

x = 360/40

x = 9°

Measure of all angles:-

x = 9°

2x = 18°

3x = 27°

4x = 36°

5x = 45°

6x = 54°

9x = 81°

10x = 90°

Hope it helps..!!!!

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