Question

the measures of the opposite angles of a
parallelogram are (3 x -2)° and (50-x)°find the measures of each angle of parallelogram.​

Answer 1

Hope it's helpful to you :) :)

Answer 2

$\huge\mathfrak\pink{solution }$

$let \: the \: four \: angles \: of \: parallelogram \: be \: -$

$\:\angle\:a \:$

$\:\angle\:b \:$

$\:\angle\:c \:$

$\:\angle\:d \:$

$measure \: of \: opposite \: angles \: is \: given \: as \: -$

$\:\angle\:a \: = (3x - 2 )\degree$

$\:\angle\:c \: = (50 - x) \degree$

$\small \fbox { \:the \: opposite \: angles \: of \: a \: parallelogram \: are \: equal \: }$

$\red \therefore \: 3x - 2 = 50 - x$

$4x = 52$

$x = \frac{52}{4}$

$\huge\red {x = 13}$

$\therefore \: 3x - 2 = 37 \degree$

$\:\angle\:a \: = \:\angle\:c \: = 37 \degree$

$\fbox{sum \: of \: 2 \: adjacent \: angles \: of \: a \: parallelogram \: is \: 180\degree}$

$\therefore \: \:\angle\:a \: +\ \: \angle\:b \: = 180\degree$

$37 \degree + \:\angle\:b \: = 180 \degree$

$\:\angle\:b \: = 180\degree - 37 \degree \: = 143 \degree$

$\:\angle\:b = \angle\:d\: \: = 143 \degree$

$\small \fbox \green{4 \: angles \: of \: a \: parallelogram \: are \: - }$

$\huge \pink{37 \degree }$

$\huge \red{143 \degree}$

$\huge \blue{37 \degree}$

$\huge\orange{143 \degree}$

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