The measures of three sides of triangle are
(4x+67-3) an. (5x+2) om and (2x+y+4 om. Find
the perimeter of the triangle
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Answered by
2
Answer:
sides of a triangle are 3x + 4y, 4x + 3y and 5x + 5y units, where x,y>0 .The triangle is .
Step-by-step explanation:
a=3x+4y,b=4x+3y and c=5x+5y be the largest side
⇒cosC=
2ab
a
2
+b
2
−c
2
=
2(3x+4y)(4x+3y)
(3x+4y)
2
+(4x+3y)
2
−(5x+5y)
2
⇒cosC=
2(3x+4y)(4x+3y)
9x
2
+16y
2
+24xy+16x
2
+9y
2
+24xy−25x
2
−25y
2
−50xy
<0,x,y>0
⇒cosC=
2(3x+4y)(4x+3y)
−2xy
<0,x,y>0
⇒θ>90
∘
∴, the triangle is obtuse angled.
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