Question

The measures of two adjacent angles of a parallelogram are in the ratio 3:2.Find the measure of each angle of the parallelogram. {Giving answer=108,72,,108,120

Answer 1

hi frnd,

given,
measure of two angles are in ratio 3:2

let angle be 3x,2x

we know that sum of consecutive angles in parallelogram is 180°

3x+2x=180
x=36°


the angles will be 3×36,2×36,3×36,2×36

therefore angles are 108°,72°,108°,72°



hope it helped :)

Answer 2

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Let the measures of two adjacent angles, ∠A and ∠B, of parallelogram ABCD are in the ratio of 3:2.

Let ∠A = 3x and ∠B = 2x

We know that the sum of the measures of adjacent angles is 180º for a parallelogram.

∠A + ∠B = 180º

3x + 2x = 180º

5x = 180º

∠A = ∠C = 3x = 108º (Opposite angles)

∠B = ∠D = 2x = 72º (Opposite angles)

Thus, the measures of the angles of the parallelogram are 108º, 72º, 108º, and 72º.