Question

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measureof each of the angles of the parallelogram.​

Answer 1

Answer:

Let the measures of two adjacent angles, ∠A and ∠B, of parallelogram ABCD are in the ratio of 3:2.

Let ∠A = 3x and ∠B = 2x

We know that the sum of the measures of adjacent angles is 180º for a parallelogram.

angle A + angle B =180

3x + 2x = 180

5x =180

x =180/5

x = 36

A = ∠C = 3x = 108º (Opposite angles)

∠B = ∠D = 2x = 72º (Opposite angles)

Thus, the measures of the angles of the parallelogram are 108º, 72º, 108º, and 72º.

Answer 2

Answer:

108°, 72°

Step-by-step explanation:

Since the adjacent angles of a parallelogram are supplementary (meaning the angles make a sum of 180°) we will add the ratios 3+2=5.

1st angle= 3/5*180

= 108°

2nd angle= 2/5*180

= 72°

Hopefully it will help....

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