Math, asked by whatthefuck31, 5 months ago

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram..​

Answers

Answered by routprabasnandan
0

Step-by-step explanation:

verification

\begin{lgathered}\begin{gathered}\\ \\ \sf \to 3x + 2x = 180 \\ \\ \sf \to \: 3 \times 36 +2 \times 36 = 180 \\ \\ \sf \to \: 108 + 72 = 180 \\ \\ \sf \to \:180 = 180 \\ \\ \large \underline{ \pink{ \sf \: hence \: verified}} \huge \dag\end{gathered}\end{lgathered}

→3x+2x=180

→3×36+2×36=180

→108+72=180

→180=180

henceverified

Answered by Anonymous
0

 \huge \pink{\mathbb {Answer ツ}}

Let us take the two adjacent angles be 3x & 2x

Note :- Sum of the adjacent angles in a parallelogram is 180°

So, we will simply add up and equal to 180 and will get the value of x

→ 3x + 2x = 180

→ 5x = 180

→ x = 180/5

→ x = 36

Thus, we got the value of x which is 36

Now, we will simply subsitute the values

1st angle :- 3x = 3 × 36 = 108

2nd angle :- 2x = 2 × 36 = 72

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