Math, asked by Anonymous, 4 months ago

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.​

Answers

Answered by Anonymous
2

Answer:

Let the measure of two adjacent angle ∠A & ∠B of parallelogram ABCD are in the ratio 3:2.

Let ∠A=3x & ∠B=2x

We know sum of two adjacent angles of parallelogram is 180⁰

3x+2x=180⁰

5x=180⁰

x=36⁰

Hence ∠A=3x=108⁰ & ∠B=2x=72⁰

[∠A=∠C=180⁰ ] & [∠B=∠D=72⁰ ]

Answered by Anonymous
0

 \huge \pink{\mathbb {Answer ツ}}

Let us take the two adjacent angles be 3x & 2x

Note :- Sum of the adjacent angles in a parallelogram is 180°

So, we will simply add up and equal to 180 and will get the value of x

→ 3x + 2x = 180

→ 5x = 180

→ x = 180/5

→ x = 36

Thus, we got the value of x which is 36

Now, we will simply subsitute the values

1st angle :- 3x = 3 × 36 = 108

2nd angle :- 2x = 2 × 36 = 72

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