Question

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.



need answer with coding




don't answer I have the solution.....xD





LETS CHECK YOUR SPAMMING TRICKS​

Answer 1

Answer:

QUESTION

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.

ANSWER

IN ATTACHMENT

Answer 2

$\star\underline{\mathtt\orange{⫷❥Q᭄} \mathfrak\blue{u~ }\mathfrak\blue{Σ} \mathbb\purple{ §}\mathtt\orange{T} \mathbb?\pink{iOn⫸}}\star\:$

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.

${ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁ ⋆᭄ SoLuTiOn⋆᭄꧂✯ }}}}}}$

$in \:parallellogram\: opposite\: angles\: are\: equal$

$Adjacent \:angles\: of\: a\: parallelogram =180°$

$\angle A =3x$

$\angle B =2x$

$\angle A +\angle B=180°$

$3x+2x=180°$

$5x=180°$

$x=\frac{180}{5}$

${\boxed {\boxed {x=36°}}}$

$\angle A =\angle C=3x$

$=3(36)$

${\boxed {\boxed {\angle A =\angle C=108°}}}$

$\angle B =\angle D=2x$

$=2(36)$

${\boxed {\boxed {\angle B =\angle D=72°}}}$

${ { \underbrace{ \mathbb{ \red{VeRiFiCaTiOn\ }}}}}$

$Sum\: of\: angles\: of \:a\: parallelogram =360°$

$\angle A+\angle B+\angle C+\angle D=360°$

$108°+72°+108°+72°=360°$

$\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{☺︎︎Hope\:It\:Helps☺︎︎}}}}}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$