Question

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of parallelogram.​

Answer 1

Answer:

$ratio = 2:3 \\ let \: the \: two \: adjacent \: angles \: \\ be \: 2x \: and \: 3x \\ the \: sum \: of \: parallelogram \\ = 2x + 3x = 180° \\ 5x = 180° \\ x = \frac{180}{5} \\ x = 36 \\ therefore, \\ \: the \: two \: adjacent \: sides \: are \\ 3x = 3 \times 36 = 108° \\ 2x = 2 \times 36 = 72°$

Answer 2

Question:-

• The measure of two adjacent angles of a parallelogram are in the ratio of 3:2 find the measure of each parallelogram.

To Find:-

• The measure of each parallelogram.

Solution:-

• Let the first angle be ' 3x '

• Second angle be ' 2x '

As we know that:-

Sum of interior angles is 360°.

⇒ 3x + 2x + 3x + 2x = 360  

⇒ 10x = 360

⇒ x = $\frac{360}{10}$

⇒ x = 36

Hence,

• First angle is 3x = 3(36) = 108°

• Second angle is 2x = 2(36) = 72°

Hope it helps you!!(●'◡'●)