Question

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.​

Answer 1

Step-by-step explanation:

Ncert solutions

Grade 8

Mathematics

Science

Chapters in NCERT Solutions - Mathematics , Class 8

Exercises in Understanding Quadrilaterals

Question 5

Q5) The measure of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.

Solution:

Let two adjacent angles be 3x\ and\ 2x3x and 2x

Since the adjacent angles in a parallelogram are supplementary.

3x+2x=180\degree3x+2x=180°

\Rightarrow5x=180\degree⇒5x=180°

\Rightarrow x=\frac{180\degree}{5}=36\degree⇒x=

5

180°

=36°

\therefore One\ angle\ =\ 3x\ =\ 3\times36\degree=108\degree∴One angle = 3x = 3×36°=108°

And another angle = 2x=2\times36\degree=72\degree2x=2×36°=72°

Answer 2

Answer:

3x+2x = 180

5x = 180

x = 180÷5

x = 36

3x = 108

2x = 72

Adjacent angles of parallelogram = 180

Let each angle be 'x' and they are denoted as the number of options

3x + 2x = 180

5x = 180

X = 180/5

x = 36

First angle = 36*3 = 108

Second angle = 36*2 = 72