Question

the measures
of two adjacent angles
of a
parallelogram
of
7:11. Find the measures of each a
each angles
of a parallelogram​

Answer 1

Correct Question :

The Measure of two adjacent angles of a Parallelogram are in the Ratio 7:11 . Find the Measure of Each Angle of Parallelogram .

Given :

⬤ Measure of two adjacent angles of a Parallelogram are in the Ratio 7:11 .

To Find :

⬤ Measure of Each Angle of Parallelogram .

Solution :

Let :

• Measure of First Angle be 7x .
• Measure of Second Angle be 11x.

Now :

As we know that , Sum of Adjacent Angles of Parallelogram is 180 degree . Hence ,

$\sf{7x+11x=180^{\circ}}$

18x = 180

x = 180/18

x = 10

Therefore , The Value of x is 10 .

Hence ,

Measure of First Qngle = 7x

= 7(10)

= 70

Measure of Second Angle = 11x

= 11(10)

= 110

Therefore , Measure of Each Adjacent Angle of Parallelogram is 70° and 110° .

Answer 2

Step-by-step explanation:

Let :- Measure of First Angle be 7x

Measure of Second Angle be 11x.

As we know,

Sum of Adjacent Angles of Parallelogram is 180 degree .

Hence ,

7x+11x=180∘

18x = 180

x = 180/18

x = 10

Therefore, The Value of x is 10 .

Hence ,

Measure of First Qngle = 7x = 7 (10) = 70

Measure of Second Angle = 11x = 11(10) = 110

Therefore , Measure of Each Adjacent Angle of Parallelogram is 70° and 110° .

Hope this is helpful for you.