the measures of two angles of a triangle are 72degree and 58 degree, find the mesure of the third angle
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in a triangle sum of three sides always be 180
let the one side is x
so, 72 + 58 + x = 180
130 +x = 180
x = 180 - 130
x = 50
let the one side is x
so, 72 + 58 + x = 180
130 +x = 180
x = 180 - 130
x = 50
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Total sum of angles =180
Angles given =72+58= 130
Third angle =180-130=50
Angles given =72+58= 130
Third angle =180-130=50
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