The mechanical advantage of a machine is 2, it is used to raise a load of
15 kgf what effort is needed?
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7
Answer:
We are given that
Mechanical advantage = 2
Load = 15kgf
Mechanical advantage = \frac{Load}{effort}
effort
Load
Effort = \frac{Load}{effort}
effort
Load
= \frac{15}{2}
2
15
- 7.5kgf
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