Question

the median and mode of a frequency distribution are 8 and 10 respectively. The mean of the distribution will be

Answer 1

Solution :

Given median( M ) = 8,

mode ( z ) = 10 ,

Let the mean = x

mode = 3median - 2mean

=> z = 3m - 2x

=> 10 = 3× 8 - 2x

=> 2x = 24 - 10

=> 2x = 14

=> x = 14/2

=> x = 7

Therefore ,

mean of the distribution = x = 7

••••

Answer 2

3Median = 2Mean + Mode
=>3×8 = 2Mean + 10
=>Mean
$= \frac{3 \times 8 - 10}{2} \\ = \frac{24 - 10}{2} \\ = \frac{14}{2} \\ = 7$



Hope this will help you. 

If you like my answer
Please mark it as brainliest 
And 
Be my follower if possible.