Question

the median of following distribution table is 35 and the class interval is 0 to 10, 10 to 20 ,20 to 30 ,30 to 40 ,40 to 50, 50to60 and 60 to 70 and frequency is 2 ,3 ,x, 6, 5 ,3 ,2 find the value of x​

Answer 1

Answer:

rrttttttttttttttrrrrrrtrr

Answer 2

Answer:

5

Step-by-step explanation:

Given,

Class interval  frequency cumulitative frequency

0−10          2                  2

10−20          3                  5

20−30        x                  5+x

30−40          6                  11+x

40−50          5                  16+x

50−60          3                  19+x

60−70          2                  21+x

Total frequency= 21+x

=>   N=21+x

=> N / 2 = (21+x) / 2

So, CF corresponding to this is 11+x

And class corresponds to this is  30−40

So, l=30  ,  F=5+x  ,  f=6  and  h=10

Median = l + [({N/2}-F)/f] * h

35 = 30 + ([21+x/2] - 5 - x) / 6 ) * 10

Solving this, we get x = 5

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