the median of tge data 8, 9, 12, 18, (x +2), (x +4), 30, 31, 34, 39 is 24. if the numbers 8, x +4 and 39 are removed what will be the median of the new set of data formed?
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Answer:
new median = 23
Step-by-step explanation:
total no. of observations,n = 10 (even no.)
Arranged data : 8,9,12,18,(x+2),(x+4),30,31,34,39
median = 24
median= [{(n/2) +1} th term + (n/2)th term] /2
=24= [ (10/2)+1 th term + 10/2 th term ] /2
=24= [6 th term + 5 th term ]/2
=24 = { (x+2) + (x+4) }/2
=24 = (2x + 6 )/2
=24= 2(x+3)/2
=24= x+3
= x = 24-3
=x = 21
new arranged data : 9,12,18,(x+2),30,31,34
new total no. of observations,n': 7 (odd no.)
new median= (n'+1)/2 th term
new median= 8/2 th term
new median= 4 th term
new median= x+2
new median= 21+2 [x=21]
new median=23
Done ☺️☺️
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