The median of the distribution given below is 14.4. Find the value of x and y, if the total
frequence is 20.
Class 0-6, 6-12, 12-18, 18-24, 24-30
frequency = 4, x ,56, y, 1
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CI.......... .. f. ..... ...... cf
0-6 ............ 4 ........... 4
6-12 ............... x. ...... ..... 4+x
12-18................ 56 ....... 9+x
so on. ........,.... so on ...... 9+x+y
........ ,.,..,....... .......... . MN. 10+x+y
TOTAL :›--10+x+y
n=20, n/2=10
Median=14.4
Therefore median class equal to 12-18.
Therefore l equal to 12
C equal to 4 plus x
F equal to 56
And h equal to 6
Median=L+ ( n/2 - cf)÷ f ×h
......plz do solve it your self
Your answer will be
2.4×5/6=6-x
x = 4
Therefore y = 6
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