The median of the distribution given below is 14.4. Find the value of x and y. If the sum of frequency is 20.
0-6
4
6-12
x
12-18
5
18-24
y
24-30
1
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Answer:
firstcolumn-class interval
second column- frequency
third column- midpoint
fourthcolumn- comm frequency
∑f=20
x+y=10−−−−−−−−−−(1)
Median is 14.4
S0, Median class is 12−18
Median =L+
f
2
n
−C
×w
So 14.4=12+
5
2
20
−(4+x)
×6
14.4×5=60+(10−4−x)×6
72=60+60−24−6x
6x=120−24−72
6x=120−96
6x=24
x=4
from eq (1)
4+y=10⇒y=6
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