Question

the median of the following data is 28.find the value of x and y if the total frequency is 50.mark 0-7 7-14 14-21 21-28 28- 35 35- 42 42-49 no. of students 3 x. 7. 11 y 16 9

Answer 1

Answer:

X=4

y=0

Step-by-step explanation:

Marks       No. of student

0-7                        3

7-14                     x

14-21                  7

21-28                  11

28-35                  y

35-42                 16

42-49                  9

Given data

N= ∑fi

= N=3+x+7+11+y+16+9

= N=x+y+46

Since N = total frequency =50

= 50=x+y+46

Become equation is  1.

⇒x+y=4

Hence it lies in class interval 28-35

L=28,h=35-28=7, f=y, Cumulative frequency =l=28

Hence cf=3+x+7+11=21+x

And N=50

Now according to formula=l+n/2-cf/f×h

⇒28=28+25-(21+x)/y×7

⇒28-28=4-x/y×7

⇒0=4-x/y×7

⇒4-x=0

X=4

Now we take x+y=4 from equation 1

4+y=4

⇒y=0

Answer 2

Step-by-step explanation:

thank you

that is wrong means sorry