Question

the median of the numbers in a list of consecutive positive multiples of 1.2 is 25.8 what is the greatest possible number in list

Answer 1

Answer:

50.4

Step-by-step explanation:

Here the median will not be included in the data given, as 25.8 is not a multiple of 1.2.

So, n is even.

So, median = 1/2[n/2th term + (n/2 + 1)th term]

n/2th term = 1.2*n/2, (n/2+1)th term = 1.2*(n/2+1)

So, 25.8 = 1/2[1.2n/2 + 1.2(n/2+1)] = 0.6(n + 1)

n + 1 = 258 / 6 = 43

n = 42.

So, greatest possible number = 1.2*42 = 50.4

Answer 2

Answer:

50.4

Step-by-step explanation:

median is the middle term of data

here the data is in arithmetic series

1.2×1, 1.2×2, 1.2×3,...

=1.2,2.4,3.6,4.8,....

with d=1.2, a=1.2

middle term of arithmetic series is

a+(n-1)d/2=25.8

(n-1)×(1.2/2)=24.6

n-1=41

n=42

last term is a+(n-1)d = 1.2+(41×1.2)=50.4

hope this helps