The median PS,QT and RU of ∆PQR intersect at point G. If the area of ∆ PQR is 108cm² ,then find the area of quadrilateral QSGU.
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Area of quadrilateral QSGU = 36 cm² if The median PS,QT and RU of ∆PQR intersect at point G and area of ∆ PQR is 108cm²
Step-by-step explanation:
Median of a Triangle Divides a Triangle into 6 Equal Areas
Area of ∆PQR = 108 cm²
Area of Each Part = 108/6 = 18 cm²
=> Area of QSG = QGU = PGU = PGT = RGT = RGS = 18 cm²
Area of quadrilateral QSGU = Area of QSG + Area of QGU
=> Area of quadrilateral QSGU = 18 + 18
=> Area of quadrilateral QSGU = 36 cm²
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