Math, asked by 01928373892, 11 months ago

The median PS,QT and RU of ∆PQR intersect at point G. If the area of ∆ PQR is 108cm² ,then find the area of quadrilateral QSGU.

Answers

Answered by amitnrw
2

Area of quadrilateral QSGU  = 36 cm²  if The median PS,QT and RU of ∆PQR intersect at point G  and area of ∆ PQR is 108cm²

Step-by-step explanation:

Median of a Triangle Divides a Triangle into 6 Equal Areas

Area of ∆PQR  = 108 cm²

Area of Each Part = 108/6  = 18 cm²

=> Area of  QSG = QGU = PGU = PGT = RGT = RGS = 18 cm²

Area of quadrilateral QSGU  = Area of QSG  + Area of QGU

=> Area of quadrilateral QSGU  = 18 + 18

=> Area of quadrilateral QSGU  = 36 cm²

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