Math, asked by sakshinde, 11 months ago

The median weight of a group of 79 students
is found to be 55 kg 6 more students are
added to this group whose weights are
50,51,52,59.5,60,61kg. What will be the
value of median of the combined group if
the lowest and the highest weights were
53kg and 59 kg respectively?

the answer is given 55
plzz explain​

Answers

Answered by hukam0685
16

Answer:

Median weight is 55 kg again.

Step-by-step explanation:

We know that Median of ungrouped data can be calculated with the following process:

  1. All the raw data should arranged in ascending order.
  2. If total numbers are n ; when n= odd; their is only one median data {( \frac{n  + 1}{2} })^{th}  \: term \\
  3. In case if n is even,then the average of n/2 and (n/2+1)th term is median.

Now,ATQ the median weight of a group of 79 students is found to be 55 kg.

Since n= 79,odd

Median is (79+1)/2= 40 th term

Since for finding Median data is already arranged in ascending order.

Now,6 more students are

added to this group whose weights are

50,51,52,59.5,60,61kg.

Here you can observed that 79+6= 85

again odd number;

Median is (85+1)/2=43 th data

Since numbers has to arranged in ascending order again,here we can analyse that50,51,52 are to arranged before 55(Median weight earlier) and 59.5,60,61kg are arranged according after 55.

No now 43th term is again 55.

Hope it helps you.

Answered by heetraj
5

Step-by-step explanation:

Answer:

Median weight is 55 kg again.

Step-by-step explanation:

We know that Median of ungrouped data can be calculated with the following process:

All the raw data should arranged in ascending order.

If total numbers are n ; when n= odd; their is only one median data\begin{lgathered}{( \frac{n + 1}{2} })^{th} \: term \\\end{lgathered}

(

2

n+1

)

th

term

In case if n is even,then the average of n/2 and (n/2+1)th term is median.

Now,ATQ the median weight of a group of 79 students is found to be 55 kg.

Since n= 79,odd

Median is (79+1)/2= 40 th term

Since for finding Median data is already arranged in ascending order.

Now,6 more students are

added to this group whose weights are

50,51,52,59.5,60,61kg.

Here you can observed that 79+6= 85

again odd number;

Median is (85+1)/2=43 th data

Since numbers has to arranged in ascending order again,here we can analyse that50,51,52 are to arranged before 55(Median weight earlier) and 59.5,60,61kg are arranged according after 55.

No now 43th term is again 55.

Hope it helps you.

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