Question

The medians BE and CF of triangle ABC intersect at G. GB and GC are bisected at H and K respectively. Prove that HKEF is a parallelogram. hence prove that G is a point of trisection of Be and CF.​

Answer 1

Answer:

hkef is parallelogram.and fk and he are diagonals of hkef . diagonals of parallelogram bisects.

so gf=gk as k bisects gc so gk = kc

therefore gf=kc=gk.

similarly ge=gh=bh