Chemistry, asked by superiortanu12378, 1 year ago

The melting points of 3 solids X,Y and Z are 298 k, 314 k and 398 k, respectively. Arrange these in increasing order of their interparticle forces of attraction

Answers

Answered by jtg07
2

Answer:

the ascending order is as follows:

Explanation:

•least is z>y>x

Answered by Anonymous
9

Given :-

Melting point of X = 298 k

Melting point of Y = 314 K

Melting point of Z = 398 K

To arrange:-

Arrange them in Increasing order of their interparticle force of attraction.

Ans :- Z > Y > X

Explanation :-

Case :- 1

The melting point of solid X is higher that means it need more heat to break the attraction force between their particle.

Case :-2

The melting points of solid Y is 314 k that means the interparticle force is also greater in comparison of solid Z.

Case :- 3

The melting point of solid Z is low that means it requires minimum heat to break the attraction forces between its particle.

The melting point is directly is proportional to the interparticle attraction forces.

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