The melting points of 3 solids X,Y and Z are 298 k, 314 k and 398 k, respectively. Arrange these in increasing order of their interparticle forces of attraction
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Answer:
the ascending order is as follows:
Explanation:
•least is z>y>x
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Given :-
Melting point of X = 298 k
Melting point of Y = 314 K
Melting point of Z = 398 K
To arrange:-
Arrange them in Increasing order of their interparticle force of attraction.
Ans :- Z > Y > X
Explanation :-
Case :- 1
The melting point of solid X is higher that means it need more heat to break the attraction force between their particle.
Case :-2
The melting points of solid Y is 314 k that means the interparticle force is also greater in comparison of solid Z.
Case :- 3
The melting point of solid Z is low that means it requires minimum heat to break the attraction forces between its particle.
The melting point is directly is proportional to the interparticle attraction forces.
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