Question

The melting points of three solids A, B and C is 360K, 280K, and 320K respectively. Arrange the three solids in the order of increasing force of attraction acting between their particles


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Answer 1

Answer:

answer is c,b,a

Explanation:

Question

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The melting points of three solids X, Y and Z are 298K, 310K and 400K, respectively. Arrange these in increasing order of their inter-particle force of attraction.

Medium

Solution

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Intermolecular forces are the forces which mediate an interaction between molecules, including forces of attraction or repulsion which act between molecules and other types of neighboring particles, e.g., atoms or ions. Intermolecular forces are weak relative to intramolecular forces – the forces which hold a molecule together.

The molecules having high melting points will have high intermolecular forces and hence the order of intermolecular forces is X<Y<Z

Answer 2

Answer:

Explanation:

Force of attraction :

The force of attraction is a force that attracts the body closer together. In nature, there are several attracting forces at work. Some of them are magnetic force, electric force, electrostatic force and gravitational force.

Given:

The three solid melting points A,B and C are $360K, 280K$ and $320K$.

Find:

Organize the three solids in ascending order of the force of attraction between their particles.

Solution:

Melting point ∞ force of attraction

Hence, a particle with a high melting point will be attracted by a strong force.

Therefore, Particle C has the highest melting point, followed by B, and finally A.

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