Chemistry, asked by lalipremlama3795, 1 year ago

The metal ion which is NOT coloured, is
a) Fe³⁺
b) V²⁺
c) Zn²⁺
d) Ti³⁺

Answers

Answered by Anonymous
4
Hola mate !! ✌️✌️

here's your answer ...⬇️⬇️

Zn2+ is not coloured

▶️so your answer is C.

➡️this is so because this ion has d10 configuration, that is, its d orbital is fully filled. hence due to extra stability its electron are not excited . hence , it is not coloured.

hope it helps !! ❤️❤️

Anonymous: thank you ^_^
Answered by qwmagpies
1

The correct option is c.

  • The metal ion which shows electronic transition shows intense colour.
  • The valance shell electronic configuration of Fe^{+3} is-
  •  {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{6}  {3d}^{5}
  • Thus it is stable but shows electronic transition and give colour.
  • The valance shell electronic configuration of V^{+2} is-
  • {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{6}  {3d}^{3}
  • It has unpaired electrons in 3d orbital so, it shows electronic transition and gives colour.
  • The valance shell electronic configuration of Zn^{+2} is-
  • {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{6}  {3d}^{10}
  • Thus it has filled d orbital and no unpaired electron. So, it does not undergo electronic transition and remains colourless.
  • The valance shell electronic configuration of Ti^{+3} is-
  • {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{6}  {3d}^{1}
  • It has unpaired electrons in 3d orbital so, it shows electronic transition and gives colour.
Similar questions