Question

The metallic bob of a simple pendulum of mass 0.5
ko carries a positive charge of 0.25 C. If the pendu-
Jum is suspended in an electric field of strength 15 N
C-1 directed from east to west, state the forces acting
on the bob and derive the condition for equilibrium.
Also find the angle subtended at the equilibrium.
(Take g = 10 m s-2)​

Answer 1

Answer:

FORCES ACTING : ELECTROSTATIC , WEIGHT & TENSION DUE TO STRING

ELECTROSTATIC FORCE=15 * 0.25 N FROM E TO W

WEIGHT=0.5 * 10 =5N

TENSION=T

LET ANGLE MADE WITH VERTICAL BE \Theta (CLOCKWISE FROM VERTICAL)

THE

T sin(theta)=5N

T cos(theta)=15/4 N

therefore, tan(theta)=3/4

hence angle is 37 degress. please follow me and mark me as brain list