Question

The mid point of a line segment is (6,_1) if one end point is (2,6) .Find the second end point​

Answer 1

Answer:

16

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given:-

The mid point of a line segment is (6,_1) and one end point is (2,6) .

To find:-

Find the second end point?

Solution:-

Let the second end point of a line be (x2, y2)

One end point = (2,6)

Let (x1, y1)=(2,6)=>x1=2 and y2=6

The mid point of a linesegment joining the points (x1, y1) and (x2, y2) is denoted by M(x,y) and defined by

[(x1+x2)/2 , (y1+y2)/2]

=>M(x,y)=[(2+x2)/2 , (6+y2)/2]

According to the given problem

Mid point of the given linesegment = (6,-1)

=>[(2+x2)/2 , (6+y2)/2] = (6,-1)

On comparing both sides then

=>(2+x2)/2=6 and (6+y2)/2=-1

=>2+x2=6×2 and 6+y2=-1×2

=>2+x2=12 and 6+y2=-2

=>x2=12-2 and y2=-2-6

=>x2=10 and y2=-8

(x2, y2)=(10,-8)

The required point =(10,-8)

Answer:-

The second end point of the given line segment is (10,-8)

Check:-

We have (x1, y1)=(2,6)=>x1=2 and y2=6

(x2, y2)=(10,-8)=>x2=10 and y2=-8

Mid Point = [(x1+x2)/2 , (y1+y2)/2]

=>M(x,y)=[(2+10)/2 ,(6-8)/2]

=>M(x,y)=(12/2,-2/2)

M(x,y)=(6,-1)

Verified the given relation.

Used formula:-

The mid point of a linesegment joining the points (x1, y1) and (x2, y2) is denoted by M(x,y) and defined by

[(x1+x2)/2 , (y1+y2)/2]