Question

The mid point of point (4,-5) and (4,15) is:​

Answer 1

Answer:

-0,5 and 9,5

I hope it is helpful

Answer 2

SOLUTION

TO DETERMINE

The mid point of point (4,-5) and (4,15)

FORMULA TO BE IMPLEMENTED

For the given two points $\sf{A( x_1 , y_1) \: \: and \: \: B( x_2 , y_2)}$

The midpoint of the line AB is

$\displaystyle \sf{ \bigg( \frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} \bigg)}$

EVALUATION

Here the given points are (4,-5) and (4,15)

Hence the required mid point of point (4,-5) and (4,15) is

$\displaystyle \sf{ = \bigg( \frac{4 + 4 }{2} , \frac{ - 5+ 15}{2} \bigg)}$

$\displaystyle \sf{ = \bigg( \frac{8 }{2} , \frac{ 10}{2} \bigg)}$

= (4,5)

FINAL ANSWER

The mid point of point (4,-5) and (4,15) is (4, 5)

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