Question

The mid-point of points A(1, 5) and C(–2, 2) is equal to

Answer 1

Hey Dear,

◆ Answer -

(-0.5, 3.5)

● Explaination -

Let B(x,y) be the midpoint of points A(x1,y1) and C(x2,y2).

Given that -

x1 = 1

y1 = 5

x2 = -2

y2 = 2

X-coordinate of midloint B is calculated as -

x = (x1 + x2) / 2

x = (1 - 2) / 2

x = -1/2

x = -0.5

Y-coordinate of midloint B is calculated as -

y = (y1 + y2) / 2

y = (5 + 2) / 2

y = 7/2

y = 3.5

Therefore, midpoint B will have co-ordinates (-0.5, 3.5).

Thanks dear...

Answer 2

Answer:

( - 1/2, 7/2)

Step-by-step explanation:

Let's first understand the question ;

The mid-point of points A(1, 5) and C(–2, 2) will be the point which will lie halfway between the line segments joining the given points.

Hence, The coordinates of this mid point will be the sum of half of the coordinates of A & C.

Consider the line joining A(x, y) & B ( m, n), The mid point of such line is given as stated above

( x/2 + m/2, y/2 + n/2)

which can be generalized as

$\frac{x +m }{2} , \frac{ y+n }{2}$

Now in this case,

(x, y) = 1, 5

( m, n) = - 2, 2

So, Mid point is given by,

$= \frac{1 - 2}{2} , \frac{5 + 2}{2} \\ \\ = \frac{ - 1}{2}, \frac{7}{2} \\ \\ = - 0.5, \: 3.5$

Therefore, Mid point of the line segment joining A(1, 5) and C(–2, 2) is (-1/2, 7/2)