Question

The mid-point of the line segment joining the points A (2, −5) and B (4, −1) is _______.

Answer 1

Answer:

Hey mate

Here your answer

Mid point formula

$( \frac{x1 + x2}{2} ) \: ( \frac{y1 + y2}{2} )$

$( \frac{2 + 4}{2} ) \: ( \frac{ - 5 - 1}{2} )$

$( \frac{6}{2} ) \: ( \frac{ - 6}{2} )$

$(3) \: ( - 3)$

Mid point of (3, - 3)

Answer 2

Step-by-step explanation:

Mid-point of a line segment joining two points $\text{\( \tt \left(x_{1}, y_{1}\right) \) and \( \tt \left(x_{2}, y_{2}\right) \)}$

is given by $\text{\( \tt \left(\dfrac{x_{1}+x_{2}}{2}, \dfrac{y_{1}+y_{2}}{2}\right) \).}$

Let M(x, y) be the midpoint of line segment joining A(2,-5) and B(4 , -1) , where

$\tt \implies \: x_{1}=2, x_{2}=4, y_{1}= - 5, y_{2} = - 1$

$\pmb {\text{then} \: \: \: \tt x = \dfrac{2 + 4}{2} = \dfrac{6}{2} = 3}$

$\pmb{ \tt \: and \: \: \: y = \dfrac{( - 5) + ( - 1)}{2} = \dfrac{ - 5 - 1}{2} = \dfrac{ - 6}{2} = - 3}$

Hence the required point is M(3,-3).