- The mid-points of AB, BC and CA of AABC are
(6, -1), (-4, -3), (2, -5). The centroid of the
AABC is
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coordinates of g = 6+(-4)+2/3 and -1-3-5/3
ie co-ordinate of g = 4/3 and -3
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Using the formula
x1+x2+x3 y1+y3+y3
------------------ -----------------
3 3
6+(-4)+2 -1-3-5
------------- -------------------
3 3
4/3 -3
The centroid of triangle ABC is ( 4/3 , -3)
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