Question

The mid value of a class interval is 42 and the class size is 10.find the lower and upper mark of given interval

Answer 1

Hey.. I think this can be ur answer dea

Mv=42

C=10

So,
Upper limit of class = mv + c/2 = 42+10/2=47

Lower limit of class = mv - c/2 = 42-10/2=37

So the class is 37-47

Hope it helps you dear ☺️☺️