Math, asked by vemularajeshwari007, 4 days ago

the mid-value of a class intervals is 12.5 and size is 5 then find the upper and lower limits of that class​

Answers

Answered by kps26092009
0

Answer:

Step-by-step explanation:

⇒  Let upper limit and lower limit be x and y

⇒    

2

x+y

=42                   [ Given ]

∴  x+y=84                     ------ ( 1 )

Now, according to the question,

⇒  x−y=10                  ------ ( 2 )

Adding equation ( 1 ) and ( 2 ) we get,

2x=94

∴  x=47

And 47−y=10

∴  y=37

∴  Required class interval =37−47

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