Question

the mid value of class interval is 42 and the class size is 10 the lower limit and upper limit are​

Answer 1

Step-by-step explanation:

Let the upper limit and lower limit of the class be x , y

then (x+y)/2 = 42

or x+y = 84

x-y = 10

solving equations x = 47 , y = 37

Answer 2

Answer:

lower limit is 37 and upper limit is 47

Step-by-step explanation: