Question

the middle digit of 100 and 1000 is 0 and sum of the sigit of the number is 12 if the digit in units place and hundreds place are interchanged. the numbers increase by 396. find the number.
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Answer 1

Answer:

Let x be the digit in units' place and y be the digit in hundreds' place.

Then, since the digit in tens' place is 0, the number will be represented by 100y + x.

If the digits are reversed, the number so formed will be represented by 100x +y. Therefore,

100x+y−(100y+x)=495

or 100x+y−100y−x=495

or 99x−99y=495

or x−y=5 ............. (1)

Again, since the sum of the other digits is 11, and the middle one is 0, we have

x+y=11 ......... (2)

From (1) and (2), we get x=8,y=3

Hence, the number is 308.

Step-by-step explanation:

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