The middle digit of a number between 100 and 1000 is zero and the sum of the other digit is 13.If the digits are reversed, the number so formed exceeds the original number by495. Find the number
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let the no. be abc where b=0
a+c=13
the no. is between 100-1000
therefore the no.s are 409,508,607,706,805,904
abc+495 = cba [given]
since the difference is 495
the no is 409
CHECKING THE ANS
904-409=495
MARK AS BRAINLIEST PLZZ
a+c=13
the no. is between 100-1000
therefore the no.s are 409,508,607,706,805,904
abc+495 = cba [given]
since the difference is 495
the no is 409
CHECKING THE ANS
904-409=495
MARK AS BRAINLIEST PLZZ
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