the middle of a three digit number is 0 and the sum of the other two digit is 10. iif the number is subtracted from the number formed after reversing the digits ,the difference is 396,find the number.
amar8605:
703-307=396
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Hi friend✌
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Let the middle of the three digit number be zero.
Let the first digit be -> x
Let the last digit be -> y
If we put 7 at the place of x and 3 at the place of y,
we see that the number formed is 703 - equation (i)
On reversing the digits,
we see that the number formed is 307 - equation (ii)
equation (i) - equation (ii)
703 -307 = 396
Hope it helps
_______________________________
Let the middle of the three digit number be zero.
Let the first digit be -> x
Let the last digit be -> y
If we put 7 at the place of x and 3 at the place of y,
we see that the number formed is 703 - equation (i)
On reversing the digits,
we see that the number formed is 307 - equation (ii)
equation (i) - equation (ii)
703 -307 = 396
Hope it helps
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