The middle of the three numbers is continued proportion is 15 and the sum of the first and third is 34, find the numbers?
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Let the numbers be x, y, z.
As the numbers are in continued proportion, therefore
y2 = xz ……………… (1)
Also, the mean proportion = 12
∴ y = √xz = 15
⇒ xz = 225…………… (2)
It is given that the sum of remaining two numbers = 34
∴ x + z = 34
⇒ x = 34 – z
Put the value of x in equation (2):
(34– z)z = 225
⇒ 34z – z2 = 225
⇒ z2 – 34z + 225= 0
⇒ z2 – 25z – 9z + 225 = 0
⇒ z(z - 25) -9(z-25) = 0
⇒ (z - 9)(z - 25) = 0
⇒ z = 9or z = 25
∴ x = 34 – 9or x = 34– 25
⇒ x = 25or x = 9.
y=15
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